How to get the path last element using xslt

[shiney_98]

Hi,
I have a param in xslt . For Example, <xsl:param name="filePath"/>

The filepath is something like C:\xml\inwork\bookmap\preview\lessonName
I need to print exactly the lessonName in the attribute value.

I tried using <substring-after($filePath, '/')[last[])"/>
and <substring-after((tokenize($filePath, '/')[last[])"/> , but it is not working

Any possible solutions?

[xephon]

You have to tokenize the path based on the separator.

[Radu]

Hi,

Also use the XSLT tokenize function as "substring-after" returns the first occurrence of the match.
Something like:

Code: Select all

<xsl:value-of select="tokenize($filePath, '\\')[last()]"/>

Regards,
Radu

[shiney_98]

Thank u Radu